The complex, [Pt(Py)(NH3)BrCl] will have how many geometrical isomers?
- 3
- 4
- 0
- 2
Answer
(1) 3
Solution
Pt2+ (5d8) forms a square planar complex; here all four ligands (Py, NH3, Br-, Cl-) are different, i.e. type [Mabcd].
As per NCERT, a square planar complex of the type [Mabcd] shows three geometrical isomers.
Fixing Py, the ligand trans to it can be NH3, Br- or Cl-
Number of geometrical isomers = 3
Answer: (1)