The d-electron configurations of Cr2+, Mn2+, Fe2+ and Co2+ are d4, d5, d6 and d7 respectively. Which one of the following will exhibit minimum paramagnetic behaviour? (At. Nos. Cr = 24, Mn = 25, Fe = 26, Co = 27)
- [Mn(H2O)6]2+
- [Fe(H2O)6]2+
- [Co(H2O)6]2+
- [Cr(H2O)6]2+
Answer
(3) [Co(H2O)6]2+
Solution
H2O is a weak field ligand, so all four are high spin (outer orbital) complexes and the d electrons stay unpaired as far as possible.
Mn2+ (d5): 5 unpaired electrons
Fe2+ (d6): 4 unpaired electrons
Co2+ (d7): 3 unpaired electrons
Cr2+ (d4): 4 unpaired electrons
= n(n+2) BM, fewest unpaired electrons means minimum paramagnetism.
[Co(H2O)6]2+ ( = 15 3.87 BM) is the least paramagnetic.
Answer: (3)