A current of 30 A each flows in opposite directions in two conducting wires, placed parallel to each other at a distance of 8 cm. The magnetic field at the mid point between the two wires is μT. ( 04 =10-7 N/A2)
- 30
- 300
- 150
- 0.0
Answer
(2) 300
Solution
[figure]
Field of a long straight wire: B= 0 I2 r= 04 2Ir
Mid point M is r=4 cm =0.04 m from each wire.
∵ The currents are opposite, by the right-hand rule both fields at M point the same way ⇒ they add.
B=2 10-7 2 300.04
⇒ B=3 10-4 T
∴ B=300
Answer: (2)