The rain drop of mass 1 g, starts with zero velocity from a height of 1 km. It hits the ground with a speed of 5 m/s. The work done by the unknown resistive force is J. (take g = 10 m/s2)
- -8.75
- -8.35
- -9.55
- -9.98
Answer
(4) -9.98
Solution
Work–energy theorem from the start (rest) to the ground:
Wg+Wr= 12mv2-0
m=1 g=10-3 kg, h=1 km =1000 m
Wg=mgh=10-3 10 1000=10 J
12mv2= 12 10-3 (5)2=0.0125 J
∴ Wr=0.0125-10=-9.9875 J -9.98 J
(Negative, ∵ the resistive force opposes the motion.)
Answer: (4)