A smooth inclined plane ends in a vertical circular loop, as shown in the figure. A small body is released from height h as shown. If the body exerts a force of three times its weight on the plane at the highest point of circle then the height h= R. The value of is . [figure]
- 2
- 4
- 3
- 6
Answer
(2) 4
Solution
[figure]
At the highest point the track pushes the body towards the centre with N=3mg (equal and opposite to the force the body exerts), and mg also acts towards the centre:
N+mg= mv2R ⇒ 3mg+mg= mv2R
⇒ v2=4gR
Smooth track ⇒ mechanical energy is conserved from the release point to the top of the loop (height 2R):
mgh=mg(2R)+ 12mv2
⇒ h=2R+ v22g=2R+ 4gR2g=4R
∴ =4
Answer: (2)