The equilibrium constants of the following are N2 + 3H2 2NH3; K1 N2 + O2 2NO; K2 H2 + 12O2 H2O; K3 The equilibrium constant (K) of the reaction : 2NH3 + 52O2 2NO + 3H2O will be
- K2K33/K1
- K2K3/K1
- K23K3/K1
- K1K33/K2
Answer
(1) K2K33/K1
Solution
Required: 2NH3 + 52O2 2NO + 3H2O
Reverse of reaction 1: 2NH3 N2 + 3H2; 1K1
Reaction 2 as such: N2 + O2 2NO; K2
Reaction 3 × 3: 3H2 + 32O2 3H2O; K33
Adding the three equations gives the required reaction, so the constants multiply:
∴ K = 1K1 K2 K33 = K2K33K1
Answer: (1)