Let a = 2 i - j + k and b = j + 2 k, Z be two vectors. Let c = a b and d be a vector of magnitude 2 in yz-plane. If | c| = 53, then the maximum possible value of ( c d)2 is equal to :
- 52
- 26
- 104
- 208
Answer
(4) 208
Solution
c = vmatrix i & j & k \ 2 & -1 & 1 \ 0 & & 2 vmatrix = -( + 2) i - 4 j + 2 k
| c|2 = 53 ( + 2)2 + 16 + 4 2 = 53
5 2 + 4 - 33 = 0 ( + 3)(5 - 11) = 0
Z = -3 c = i - 4 j - 6 k
d = d2 j + d3 k with d22 + d32 = 4
c d = -4d2 - 6d3
( c d)2 (16 + 36)(d22 + d32) = 52 4 = 208 (Cauchy–Schwarz)
Maximum value = 208
Answer: (4)