Consider the following data : f H (methane, g) = -X kJ mol-1 Enthalpy of sublimation of graphite = Y kJ mol-1 Dissociation enthalpy of H2 = Z kJ mol-1 The bond enthalpy of C–H bond is given by :
- X+Y+2Z4
- X+Y+4Z2
- -X+Y+Z4
- X+Y+Z
Answer
(1) X+Y+2Z4
Solution
Formation of methane: C(graphite) + 2H2(g) CH4(g); f H = -X
Break it into steps (let C–H bond enthalpy = ):
C(graphite) C(g); H = Y
2H2(g) 4H(g); H = 2Z
C(g) + 4H(g) CH4(g); H = -4
By Hess's law: -X = Y + 2Z - 4
4 = X + Y + 2Z
= X+Y+2Z4
Answer: (1)