Resonance in X2Y can be represented as [figure] The enthalpy of formation of X2Y ( X X(g) + 12Y = Y(g) X2Y(g) ) is 80 kJ mol-1. The magnitude of resonance energy of X2Y is kJ mol-1 (nearest integer value). Given: Bond energies of X X, X = X, Y = Y and X = Y are 940, 410, 500, and 602 kJ mol-1 respectively. Valence X: 3, Y: 2
Answer
98
Solution
Formation reaction: X X(g) + 12Y = Y(g) X = X = Y(g)
Energy absorbed (bonds broken) = X X + 12 Y = Y = 940 + 250 = 1190 kJ mol-1
Energy released (bonds formed in the structure X = X = Y) = X = X + X = Y = 410 + 602 = 1012 kJ mol-1
f H(calculated) = 1190 - 1012 = 178 kJ mol-1
The actual (resonance-stabilised) molecule has f H = 80 kJ mol-1.
Resonance energy = 178 - 80 = 98 kJ mol-1
Answer: 98