CH3CHO and C6H5CH2CHO can be distinguished chemically by
- Benedict's test
- Iodoform test
- Tollens' reagent test
- Fehling's solution test
Answer
(2) Iodoform test
Solution
Both are aldehydes with α-hydrogens, so both reduce Tollens' reagent, Fehling's solution and Benedict's solution.
As per NCERT, compounds having a CH3CO- group (methyl ketones and acetaldehyde) give the iodoform test.
CH3CHO+3I2+4NaOH CHI3 (yellow)+HCOONa+3NaI+3H2O
C6H5CH2CHO has no CH3CO- group no iodoform.
Answer: (2)