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Amines · Question 25

NEET 2017MCQEasy📈 Topic in 75% papers+4−1
1

Which of the following reactions is appropriate for converting acetamide to methanamine?

  1. Hoffmann hypobromamide reaction
  2. Stephen's reaction
  3. Gabriel phthalimide synthesis
  4. Carbylamine reaction

Answer

(1) Hoffmann hypobromamide reaction

Solution

Acetamide (CH3CONH2, 2 C) → methanamine (CH3NH2, 1 C): one carbon atom less.

As per NCERT, Hoffmann bromamide degradation converts an amide into a primary amine with one carbon atom less than the amide:

CH3CONH2 + Br2 + 4NaOH CH3NH2 + Na2CO3 + 2NaBr + 2H2O

Stephen's reaction gives aldehydes from nitriles, Gabriel synthesis gives amines from alkyl halides, and the carbylamine reaction gives isocyanides.

Answer: (1)

NEET 2017

Keep practising — Amines

2

The correct statement regarding the basicity of arylamines is

  1. arylamines are generally more basic than alkylamines because of aryl group
  2. arylamines are generally more basic than alkylamines, because the nitrogen atom in arylamines is sp-hybridised
  3. arylamines are generally less basic than alkylamines because the nitrogen lone-pair electrons are delocalised by interaction with the aromatic ring -electron system
  4. arylamines are generally more basic than alkylamines because the nitrogen lone-pair electrons are not delocalised by interaction with the aromatic ring -electron system.
NEET 2016 (Phase 1)
3

Which one of the following nitro-compounds does not react with nitrous acid?

  1. [figure]
  2. [figure]
  3. [figure]
  4. [figure]
NEET 2016 (Phase 2)
4

A given nitrogen-containing aromatic compound 'A' reacts with Sn/HCl, followed by HNO2 to give an unstable compound 'B'. 'B', on treatment with phenol, forms a beautiful coloured compound 'C' with the molecular formula C12H10N2O. The structure of compound 'A' is

  1. [figure]
  2. [figure]
  3. [figure]
  4. [figure]
NEET 2016 (Phase 2)
5

The following reaction [figure] is known by the name

  1. Perkin's reaction
  2. Acetylation reaction
  3. Schotten-Baumann reaction
  4. Friedel-Craft's reaction
AIPMT 2015
6

Method by which aniline cannot be prepared is

  1. degradation of benzamide with bromine in alkaline solution
  2. reduction of nitrobenzene with H2/Pd in ethanol
  3. potassium salt of phthalimide treated with chlorobenzene followed by hydrolysis with aqueous NaOH solution
  4. hydrolysis of phenylisocyanide with acidic solution.
AIPMT 2015
7

The electrolytic reduction of nitrobenzene in strongly acidic medium produces

  1. azobenzene
  2. aniline
  3. p-aminophenol
  4. azoxybenzene.
AIPMT 2015 (Cancelled)
8

In the following reaction, the product (A) is [figure]

  1. [figure]
  2. [figure]
  3. [figure]
  4. [figure]
AIPMT 2014
9

Which of the following will be most stable diazonium salt RN2+X-?

  1. CH3N2+X-
  2. C6H5N2+X-
  3. CH3CH2N2+X-
  4. C6H5CH2N2+X-
AIPMT 2014
10

In the reaction [figure] A is

  1. H3PO2 and H2O
  2. H+/H2O
  3. HgSO4/H2SO4
  4. Cu2Cl2
NEET 2013
11

On hydrolysis of a "compound", two compounds are obtained. One of which on treatment with sodium nitrite and hydrochloric acid gives a product which does not respond to iodoform test. The second one reduces Tollens reagent and Fehling's solution. The "compound" is

  1. CH3CH2CH2NC
  2. CH3CH2CH2CN
  3. CH3CH2CH2ON=O
  4. CH3CH2CH2CON(CH3)2
NEET 2013 (Karnataka)

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