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Amines · Question 30

AIPMT 2015MCQEasy📈 Topic in 75% papers+4−1
1

Method by which aniline cannot be prepared is

  1. degradation of benzamide with bromine in alkaline solution
  2. reduction of nitrobenzene with H2/Pd in ethanol
  3. potassium salt of phthalimide treated with chlorobenzene followed by hydrolysis with aqueous NaOH solution
  4. hydrolysis of phenylisocyanide with acidic solution.

Answer

(3) potassium salt of phthalimide treated with chlorobenzene followed by hydrolysis with aqueous NaOH solution

Solution

(1) Hoffmann bromamide degradation: C6H5CONH2 + Br2 + 4NaOH C6H5NH2 + Na2CO3 + 2NaBr + 2H2O ✓

(2) C6H5NO2 H2/Pd, ethanol C6H5NH2 ✓

(4) C6H5NC + 2H2O H+ C6H5NH2 + HCOOH ✓

(3) As per NCERT, aromatic primary amines cannot be prepared by Gabriel phthalimide synthesis, because aryl halides do not undergo nucleophilic substitution with the anion formed by phthalimide.

∴ Aniline cannot be prepared by method (3).

Answer: (3)

AIPMT 2015

Keep practising — Amines

2

The electrolytic reduction of nitrobenzene in strongly acidic medium produces

  1. azobenzene
  2. aniline
  3. p-aminophenol
  4. azoxybenzene.
AIPMT 2015 (Cancelled)
3

In the following reaction, the product (A) is [figure]

  1. [figure]
  2. [figure]
  3. [figure]
  4. [figure]
AIPMT 2014
4

Which of the following will be most stable diazonium salt RN2+X-?

  1. CH3N2+X-
  2. C6H5N2+X-
  3. CH3CH2N2+X-
  4. C6H5CH2N2+X-
AIPMT 2014
5

In the reaction [figure] A is

  1. H3PO2 and H2O
  2. H+/H2O
  3. HgSO4/H2SO4
  4. Cu2Cl2
NEET 2013
6

On hydrolysis of a "compound", two compounds are obtained. One of which on treatment with sodium nitrite and hydrochloric acid gives a product which does not respond to iodoform test. The second one reduces Tollens reagent and Fehling's solution. The "compound" is

  1. CH3CH2CH2NC
  2. CH3CH2CH2CN
  3. CH3CH2CH2ON=O
  4. CH3CH2CH2CON(CH3)2
NEET 2013 (Karnataka)
7

Some reactions of amines are given. Which one is not correct?

  1. [figure]
  2. CH3CH2NH2 + HNO2 CH3CH2OH + N2
  3. CH3NH2 + C6H5SO2Cl CH3NHSO2C6H5
  4. (CH3)2NH + NaNO2 + HCl (CH3)2N-N=O
NEET 2013 (Karnataka)
8

An organic compound (C3H9N) (A), when treated with nitrous acid, gave an alcohol and N2 gas was evolved. (A) on warming with CHCl3 and caustic potash gave (C) which on reduction gave isopropylmethylamine. Predict the structure of (A)

  1. [figure]
  2. CH3CH2-NH-CH3
  3. [figure]
  4. CH3CH2CH2-NH2
AIPMT 2012 (Mains)
9

An organic compound A on treatment with NH3 gives B, which on heating gives C. C when treated with Br2 in the presence of KOH produces ethyl amine. Compound A is

  1. CH3COOH
  2. CH3CH2CH2COOH
  3. [figure]
  4. CH3CH2COOH
AIPMT 2011 (Mains)
10

Which of the following compounds is most basic?

  1. [figure]
  2. [figure]
  3. [figure]
  4. [figure]
AIPMT 2011 (Mains)
11

In a set of reactions m-bromobenzoic acid gave a product D. Identify the product D. [figure]

  1. [figure]
  2. [figure]
  3. [figure]
  4. [figure]
AIPMT 2011 (Prelims)

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