A small cube of side 1 mm is placed at the centre of a circular loop of radius 10 cm carrying a current of 2 A. The magnetic energy stored inside the cube is 10-14 J. The value of is . ( 0=4 10-7 Tm/A, =3.14)
- 6.28
- 6.28 10-6
- 628
- 6.28 10-4
Answer
(1) 6.28
Solution
Field at the centre of the loop (uniform over the tiny cube):
B= 0I2r= 4 10-7 22 0.1=4 10-6 T
Magnetic energy density:
u= B22 0= 16 2 10-122 4 10-7=2 10-5 J/m3
Volume of the cube =(10-3)3=10-9 m3
∴ U=u V=2 10-14=6.28 10-14 J ⇒ =6.28
Answer: (1)