A wire of resistance 4 is stretched to twice its original length. The resistance of stretched wire would be
- 8
- 16
- 2
- 4
Answer
(2) 16
Solution
R = lA; on stretching, the volume V = Al stays constant
⇒ A = Vl and R = l2V, i.e. R l2
l' = 2l ⇒ R' = (2)2 R = 4 4
∴ R' = 16
Answer: (2)