A 12 cm wire is given a shape of a right angled triangle ABC having sides 3 cm, 4 cm and 5 cm as shown in the figure. The resistance between two ends (AB, BC, CA) of the respective sides are measured one by one. Their ratio is [figure]
- 9 : 16 : 25
- 27 : 32 : 35
- 21 : 24 : 25
- 3 : 4 : 5
Answer
(2) 27 : 32 : 35
Solution
Resistance of the uniform wire ∝ length; take the resistance of 1 cm as .
Between the ends of one side, that side is in parallel with the other two sides in series.
RAB = 3 9 12 = 2712
RBC = 4 8 12 = 3212
RCA = 5 7 12 = 3512
∴ RAB : RBC : RCA = 27 : 32 : 35
Answer: (2)