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Current Electricity · Question 62

NEET 2013 (Karnataka)MCQEasy📈 Topic in 62% papers+4−1
1

Two rods are joined end to end, as shown. Both have a cross-sectional area of 0.01 cm2. Each is 1 meter long. One rod is of copper with a resistivity of 1.7 10-6 ohm-centimeter, the other is of iron with a resistivity of 10-5 ohm-centimeter. [figure] How much voltage is required to produce a current of 1 ampere in the rods?

  1. 0.00145 V
  2. 0.0145 V
  3. 1.7 10-6 V
  4. 0.117 V

Answer

(4) 0.117 V

Solution

R = lA, with l = 1 m = 100 cm, A = 0.01 cm2

RCu = 1.7 10-6 1000.01 = 1.7 10-2

RFe = 10-5 1000.01 = 10-1

The rods are in series:

R = 0.017 + 0.1 = 0.117

∴ V = IR = 1 0.117 = 0.117 V

Answer: (4)

NEET 2013 (Karnataka)

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2

A 12 cm wire is given a shape of a right angled triangle ABC having sides 3 cm, 4 cm and 5 cm as shown in the figure. The resistance between two ends (AB, BC, CA) of the respective sides are measured one by one. Their ratio is [figure]

  1. 9 : 16 : 25
  2. 27 : 32 : 35
  3. 21 : 24 : 25
  4. 3 : 4 : 5
NEET 2013 (Karnataka)
3

Ten identical cells connected in series are needed to heat a wire of length one meter and radius 'r' by 10 in time 't'. How many cells will be required to heat the wire of length two meter of the same radius by the same temperature in time 't' ?

  1. 20
  2. 30
  3. 40
  4. 10
NEET 2013 (Karnataka)
4

A cell having an emf and internal resistance r is connected across a variable external resistance R. As the resistance R is increased, the plot of potential difference V across R is given by

  1. [figure]
  2. [figure]
  3. [figure]
  4. [figure]
AIPMT 2012 (Mains)
5

The power dissipated in the circuit shown in the figure is 30 watts. The value of R is [figure]

  1. 20
  2. 15
  3. 10
  4. 30
AIPMT 2012 (Mains)
6

In the circuit shown the cells A and B have negligible resistances. For VA = 12 V, R1 = 500 and R = 100 the galvanometer (G) shows no deflection. The value of VB is [figure]

  1. 4 V
  2. 2 V
  3. 12 V
  4. 6 V
AIPMT 2012 (Prelims)
7

A ring is made of a wire having a resistance R0 = 12 . Find the points A and B, as shown in the figure, at which a current carrying conductor should be connected so that the resistance R of the sub circuit between these points is equal to 83 . [figure]

  1. l1l2 = 58
  2. l1l2 = 13
  3. l1l2 = 38
  4. l1l2 = 12
AIPMT 2012 (Prelims)
8

If voltage across a bulb rated 220 volt-100 watt drops by 2.5% of its rated value, the percentage of the rated value by which the power would decrease is

  1. 20%
  2. 2.5%
  3. 5%
  4. 10%
AIPMT 2012 (Prelims)
9

In the circuit shown in the figure, if the potential at point A is taken to be zero, the potential at point B is [figure]

  1. +1 V
  2. -1 V
  3. +2 V
  4. -2 V
AIPMT 2011 (Mains)
10

A current of 2 A flows through a 2 Ω resistor when connected across a battery. The same battery supplies a current of 0.5 A when connected across a 9 Ω resistor. The internal resistance of the battery is

  1. 0.5 Ω
  2. 1/3 Ω
  3. 1/4 Ω
  4. 1 Ω
AIPMT 2011 (Prelims)
11

If power dissipated in the 9 Ω resistor in the circuit shown is 36 watt, the potential difference across the 2 Ω resistor is [figure]

  1. 4 volt
  2. 8 volt
  3. 10 volt
  4. 2 volt
AIPMT 2011 (Prelims)

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