The power dissipated in the circuit shown in the figure is 30 watts. The value of R is [figure]
- 20
- 15
- 10
- 30
Answer
(3) 10
Solution
R and 5 Ω are in parallel across the 10 V cell (ideal), so each has 10 V across it.
P = V2R + V25
30 = 100R + 1005 = 100R + 20
100R = 10
R = 10
Answer: (3)