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Application of Integrals · Question 12

JEE Main 2026 (Online) 24th January Morning ShiftMCQMedium📈 Topic in 74% papers+4−1
1

Let A1 be the bounded area enclosed by the curves y = x2 + 2, x + y = 8 and y-axis that lies in the first quadrant. Let A2 be the bounded area enclosed by the curves y = x2 + 2, y2 = x, x = 2, and y-axis that lies in the first quadrant. Then A1 - A2 is equal to

  1. 23(2 2 + 1)
  2. 23(3 2 + 1)
  3. 23( 2 + 1)
  4. 23(4 2 + 1)

Answer

(1) 23(2 2 + 1)

Solution

A1: y = x2 + 2 meets x + y = 8 where x2 + x - 6 = 0 x = 2 (first quadrant).

A1 = 02 [(8 - x) - (x2 + 2) ] dx = 02 (6 - x - x2) dx

A1 = 12 - 2 - 83 = 223

A2: between y = x2 + 2 (above) and y = x (below) from x = 0 to x = 2.

A2 = 02 (x2 + 2 - x ) dx = 83 + 4 - 23(2)3/2

A2 = 203 - 4 23

A1 - A2 = 223 - 203 + 4 23 = 23(2 2 + 1)

Answer: (1)

JEE Main 2026 (Online) 24th January Morning Shift

Keep practising — Application of Integrals

2

Let f( ) denote the area of the region in the first quadrant bounded by x = 0, x = 1, y2 = x and y = | x - 5| - |1 - x| + x2. Then (f(0) + f(1)) is equal to

  1. 12
  2. 14
  3. 9
  4. 7
JEE Main 2026 (Online) 24th January Evening Shift
3

Let the area of the region bounded by the curve y = \ x, x\, lines x = 0, x = 3 2, and the x-axis be A. Then, A + A2 is equal to .

JEE Main 2026 (Online) 23rd January Morning Shift
4

The area of the region enclosed between the circles x2 + y2 = 4 and x2 + (y - 2)2 = 4 is:

  1. 23(4 - 3 3)
  2. 43(2 - 3)
  3. 43(2 - 3 3)
  4. 23(2 - 3 3)
JEE Main 2026 (Online) 23rd January Evening Shift
5

Let the line x = -1 divide the area of the region \(x, y) : 1 + x2 y 3 - x \ in the ratio m : n, (m, n) = 1. Then m + n is equal to

  1. 27
  2. 28
  3. 25
  4. 26
JEE Main 2026 (Online) 22nd January Morning Shift
6

The area of the region A = \(x, y) : 4x2 + y2 8 and y2 4x\ is:

  1. + 23
  2. 2 + 2
  3. + 4
  4. 2 + 13
JEE Main 2026 (Online) 22nd January Evening Shift
7

The area of the region, inside the ellipse x2 + 4y2 = 4 and outside the region bounded by the curves y = |x| - 1 and y = 1 - |x|, is :

  1. 2 - 1
  2. 3( - 1)
  3. 2( - 1)
  4. 2 - 12
JEE Main 2026 (Online) 21st January Morning Shift
8

If the area of the region \(x, y) : 1 - 2x y 4 - x2, x 0, y 0\ is , , N, ( , ) = 1, then the value of ( + ) is:

  1. 73
  2. 85
  3. 67
  4. 91
JEE Main 2026 (Online) 21st January Evening Shift
9

Let the area of the bounded region \(x, y) : 0 9x y2, y 3x - 6 \ be A. Then 6A is equal to .

JEE Main 2025 (Online) 8th April Evening Shift
10

If the area of the region bounded by the curves y = 4 - x24 and y = x-42 is equal to , then 6 equals

  1. 210
  2. 250
  3. 240
  4. 220
JEE Main 2025 (Online) 7th April Morning Shift
11

If the area of the region \(x, y) : 1 + x2 y \x + 7, 11 - 3x\\ is A, then 3A is equal to :

  1. 50
  2. 46
  3. 49
  4. 47
JEE Main 2025 (Online) 7th April Evening Shift

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