The area of the region enclosed between the circles x2 + y2 = 4 and x2 + (y - 2)2 = 4 is:
- 23(4 - 3 3)
- 43(2 - 3)
- 43(2 - 3 3)
- 23(2 - 3 3)
Answer
(1) 23(4 - 3 3)
Solution
Both circles have radius 2; centres (0, 0) and (0, 2).
Points of intersection: x2 + y2 = x2 + (y - 2)2 y = 1, x = 3
The common region is symmetric about y = 1, so
Area = 2 - 3 3 ( 4 - x2 - 1 )dx = 4 0 3 ( 4 - x2 - 1 )dx
0 3 4 - x2 dx = [ x2 4 - x2 + 2 -1 x2 ]0 3 = 32 + 2 3
Area = 4 ( 32 + 2 3 - 3 ) = 8 3 - 2 3
= 23(4 - 3 3)
Answer: (1)