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Application of Integrals · Question 16

JEE Main 2026 (Online) 22nd January Morning ShiftMCQMedium📈 Topic in 74% papers+4−1
1

Let the line x = -1 divide the area of the region \(x, y) : 1 + x2 y 3 - x \ in the ratio m : n, (m, n) = 1. Then m + n is equal to

  1. 27
  2. 28
  3. 25
  4. 26

Answer

(1) 27

Solution

Intersection: 1 + x2 = 3 - x x2 + x - 2 = 0 x = -2, 1

[figure]

Let F(x) = (2 - x - x2) dx = 2x - x22 - x33

F(-2) = -4 - 2 + 83 = - 103, F(-1) = -2 - 12 + 13 = - 136, F(1) = 2 - 12 - 13 = 76

A1 = F(-1) - F(-2) = - 136 + 206 = 76

A2 = F(1) - F(-1) = 76 + 136 = 206

A1 : A2 = 7 : 20, (7, 20) = 1

m + n = 7 + 20 = 27

Answer: (1)

JEE Main 2026 (Online) 22nd January Morning Shift

Keep practising — Application of Integrals

2

The area of the region A = \(x, y) : 4x2 + y2 8 and y2 4x\ is:

  1. + 23
  2. 2 + 2
  3. + 4
  4. 2 + 13
JEE Main 2026 (Online) 22nd January Evening Shift
3

The area of the region, inside the ellipse x2 + 4y2 = 4 and outside the region bounded by the curves y = |x| - 1 and y = 1 - |x|, is :

  1. 2 - 1
  2. 3( - 1)
  3. 2( - 1)
  4. 2 - 12
JEE Main 2026 (Online) 21st January Morning Shift
4

If the area of the region \(x, y) : 1 - 2x y 4 - x2, x 0, y 0\ is , , N, ( , ) = 1, then the value of ( + ) is:

  1. 73
  2. 85
  3. 67
  4. 91
JEE Main 2026 (Online) 21st January Evening Shift
5

Let the area of the bounded region \(x, y) : 0 9x y2, y 3x - 6 \ be A. Then 6A is equal to .

JEE Main 2025 (Online) 8th April Evening Shift
6

If the area of the region bounded by the curves y = 4 - x24 and y = x-42 is equal to , then 6 equals

  1. 210
  2. 250
  3. 240
  4. 220
JEE Main 2025 (Online) 7th April Morning Shift
7

If the area of the region \(x, y) : 1 + x2 y \x + 7, 11 - 3x\\ is A, then 3A is equal to :

  1. 50
  2. 46
  3. 49
  4. 47
JEE Main 2025 (Online) 7th April Evening Shift
8

If the area of the region \(x, y) : |x - 5| y 4 x\ is A, then 3A is equal to .

JEE Main 2025 (Online) 4th April Morning Shift
9

A line passing through the point A(-2, 0) touches the parabola P: y2 = x - 2 at the point B in the first quadrant. The area of the region bounded by the line AB, parabola P and the x-axis, is :

  1. 3
  2. 73
  3. 83
  4. 2
JEE Main 2025 (Online) 4th April Evening Shift
10

The area of the region bounded by the curve y = \|x|, x|x-2|\, the x-axis and the lines x = -2 and x = 4 is equal to

JEE Main 2025 (Online) 3rd April Morning Shift
11

The area of the region \(x, y) : |x - y| y 4 x\ is

  1. 5123
  2. 20483
  3. 512
  4. 10243
JEE Main 2025 (Online) 3rd April Evening Shift

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