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Application of Integrals · Question 13

JEE Main 2026 (Online) 24th January Evening ShiftMCQEasy📈 Topic in 74% papers+4−1
1

Let f( ) denote the area of the region in the first quadrant bounded by x = 0, x = 1, y2 = x and y = | x - 5| - |1 - x| + x2. Then (f(0) + f(1)) is equal to

  1. 12
  2. 14
  3. 9
  4. 7

Answer

(4) 7

Solution

In the first quadrant y2 = x gives y = x, and 0 x 1 for 0 x 1.

α = 0: y = |-5| - |1| + 0 = 4

⇒ f(0) = 01(4 - x) dx = 4 - 23 = 103

α = 1: for 0 x 1, |x - 5| = 5 - x and |1 - x| = 1 - x

⇒ y = (5 - x) - (1 - x) + x2 = 4 + x2

⇒ f(1) = 01(4 + x2 - x) dx = 4 + 13 - 23 = 113

∴ f(0) + f(1) = 103 + 113 = 7

Answer: (4)

JEE Main 2026 (Online) 24th January Evening Shift

Keep practising — Application of Integrals

2

Let the area of the region bounded by the curve y = \ x, x\, lines x = 0, x = 3 2, and the x-axis be A. Then, A + A2 is equal to .

JEE Main 2026 (Online) 23rd January Morning Shift
3

The area of the region enclosed between the circles x2 + y2 = 4 and x2 + (y - 2)2 = 4 is:

  1. 23(4 - 3 3)
  2. 43(2 - 3)
  3. 43(2 - 3 3)
  4. 23(2 - 3 3)
JEE Main 2026 (Online) 23rd January Evening Shift
4

Let the line x = -1 divide the area of the region \(x, y) : 1 + x2 y 3 - x \ in the ratio m : n, (m, n) = 1. Then m + n is equal to

  1. 27
  2. 28
  3. 25
  4. 26
JEE Main 2026 (Online) 22nd January Morning Shift
5

The area of the region A = \(x, y) : 4x2 + y2 8 and y2 4x\ is:

  1. + 23
  2. 2 + 2
  3. + 4
  4. 2 + 13
JEE Main 2026 (Online) 22nd January Evening Shift
6

The area of the region, inside the ellipse x2 + 4y2 = 4 and outside the region bounded by the curves y = |x| - 1 and y = 1 - |x|, is :

  1. 2 - 1
  2. 3( - 1)
  3. 2( - 1)
  4. 2 - 12
JEE Main 2026 (Online) 21st January Morning Shift
7

If the area of the region \(x, y) : 1 - 2x y 4 - x2, x 0, y 0\ is , , N, ( , ) = 1, then the value of ( + ) is:

  1. 73
  2. 85
  3. 67
  4. 91
JEE Main 2026 (Online) 21st January Evening Shift
8

Let the area of the bounded region \(x, y) : 0 9x y2, y 3x - 6 \ be A. Then 6A is equal to .

JEE Main 2025 (Online) 8th April Evening Shift
9

If the area of the region bounded by the curves y = 4 - x24 and y = x-42 is equal to , then 6 equals

  1. 210
  2. 250
  3. 240
  4. 220
JEE Main 2025 (Online) 7th April Morning Shift
10

If the area of the region \(x, y) : 1 + x2 y \x + 7, 11 - 3x\\ is A, then 3A is equal to :

  1. 50
  2. 46
  3. 49
  4. 47
JEE Main 2025 (Online) 7th April Evening Shift
11

If the area of the region \(x, y) : |x - 5| y 4 x\ is A, then 3A is equal to .

JEE Main 2025 (Online) 4th April Morning Shift

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