Let f( ) denote the area of the region in the first quadrant bounded by x = 0, x = 1, y2 = x and y = | x - 5| - |1 - x| + x2. Then (f(0) + f(1)) is equal to
- 12
- 14
- 9
- 7
Answer
(4) 7
Solution
In the first quadrant y2 = x gives y = x, and 0 x 1 for 0 x 1.
α = 0: y = |-5| - |1| + 0 = 4
⇒ f(0) = 01(4 - x) dx = 4 - 23 = 103
α = 1: for 0 x 1, |x - 5| = 5 - x and |1 - x| = 1 - x
⇒ y = (5 - x) - (1 - x) + x2 = 4 + x2
⇒ f(1) = 01(4 + x2 - x) dx = 4 + 13 - 23 = 113
∴ f(0) + f(1) = 103 + 113 = 7
Answer: (4)