10 g of hydrogen and 64 g of oxygen were filled in a steel vessel and exploded. Amount of water produced in this reaction will be
- 3 mol
- 4 mol
- 1 mol
- 2 mol
Answer
(2) 4 mol
Solution
2H2(g) + O2(g) 2H2O(l)
Moles of H2 = 102 = 5 mol; moles of O2 = 6432 = 2 mol
∵ 2 mol O2 needs only 4 mol H2, O2 is the limiting reagent.
∴ Water formed = 2 2 = 4 mol
Answer: (2)