How many moles of lead (II) chloride will be formed from a reaction between 6.5 g of PbO and 3.2 g of HCl?
- 0.011
- 0.029
- 0.044
- 0.333
Answer
(2) 0.029
Solution
PbO + 2HCl PbCl2 + H2O
Moles of PbO = 6.5223 = 0.029 mol
Moles of HCl = 3.236.5 = 0.088 mol
⇒ HCl required for 0.029 mol PbO = 2 0.029 = 0.058 mol, which is less than 0.088 mol available.
∴ PbO is the limiting reagent and moles of PbCl2 formed = moles of PbO = 0.029 mol.
Answer: (2)