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Chemical Bonding and Molecular Structure · Question 9

JEE Main 2026 (Online) 2nd April Morning ShiftMCQMedium📈 Topic in 19% papers+4−1
1

Given below are two statements : In the light of the above statements, choose the correct answer from the options given below :

  1. Both Statement I and Statement II are true
  2. Both Statement I and Statement II are false
  3. Statement I is true but Statement II is false
  4. Statement I is false but Statement II is true

Answer

(3) Statement I is true but Statement II is false

Solution

MO configuration of O2 (16 electrons):

1s2 *1s2 2s2 *2s2 2pz2 ( 2px2 = 2py2) ( *2px1 = *2py1)

Bond order = 12(Nb - Na) and the unpaired electrons are those in the *2p orbitals:

O2+ (15 electrons): * electrons = 1 ⇒ B.O. = 2.5, unpaired = 1

O2 (16 electrons): * electrons = 2 ⇒ B.O. = 2, unpaired = 2

O2- (17 electrons): * electrons = 3 ⇒ B.O. = 1.5, unpaired = 1

O22- (18 electrons): * electrons = 4 ⇒ B.O. = 1, unpaired = 0

Statement I: bond length ∝ 1bond order

⇒ bond length: O2+ < O2 < O2- < O22- ∴ Statement I is true.

Statement II: unpaired electrons are 2 (O2), 1 (O2+), 1 (O2-), 0 ( O22-)

∵ O2+ and O2- have the same number (1), the order O2+ > O2- is wrong ∴ Statement II is false.

Answer: (3)

JEE Main 2026 (Online) 2nd April Morning Shift

Keep practising — Chemical Bonding and Molecular Structure

2

SF4 is isostructural with : Choose the correct answer from the options given below :

  1. C Only
  2. C and E Only
  3. A and D Only
  4. B and E Only
JEE Main 2026 (Online) 2nd April Evening Shift
3

Given below are two statements : In the light of the above statements, choose the correct answer from the options given below

  1. Both Statement I and Statement II are false
  2. Statement I is true but Statement II is false
  3. Statement I is false but Statement II is true
  4. Both Statement I and Statement II are true
JEE Main 2026 (Online) 28th January Morning Shift
4

Match List-I with List-II according to shape. Choose the correct answer from the options given below :

  1. A-II, B-III, C-I, D-IV
  2. A-III, B-II, C-IV, D-I
  3. A-II, B-III, C-IV, D-I
  4. A-II, B-I, C-III, D-IV
JEE Main 2026 (Online) 28th January Evening Shift
5

Given below are statements about some molecules/ions. Identify the CORRECT statements. Choose the correct answer from the options given below:

  1. B & C Only
  2. B, C & D Only
  3. A, C & D Only
  4. A, B, C, D & E
JEE Main 2026 (Online) 24th January Morning Shift
6

Among the following, the CORRECT combinations are Choose the correct answer from the options given below:

  1. B, C and D Only
  2. A, B, C and D
  3. A, B and C Only
  4. A and B Only
JEE Main 2026 (Online) 24th January Morning Shift
7

Pair of species among the following having same bond order as well as paramagnetic character will be-

  1. O2-, N2+
  2. O2+, N22-
  3. O2-, N2-
  4. O2+, N2-
JEE Main 2026 (Online) 24th January Evening Shift
8

Identify the molecule (X) with maximum number of lone pairs of electrons (obtained using Lewis dot structure) among HNO3, H2SO4, NF3 and O3. Choose the correct bond angle made by the central atom of the molecule (X).

  1. 107
  2. 102
  3. 120
  4. 116
JEE Main 2026 (Online) 23rd January Morning Shift
9

Which statements are NOT TRUE about XeO2F2? Choose the correct answer from the options given below :

  1. B, D and E Only
  2. B and D Only
  3. B, C and E Only
  4. A and D Only
JEE Main 2026 (Online) 23rd January Evening Shift
10

Two p-block elements X and Y form fluorides of the type EF3. The fluoride compound XF3 is a Lewis acid and YF3 is a Lewis base. The hybridizations of the central atoms of XF3 and YF3 respectively are

  1. sp2 and sp3
  2. Both sp3
  3. Both sp2
  4. sp3 and sp2
JEE Main 2026 (Online) 22nd January Morning Shift
11

The formal charges on the atoms marked as (1) to (4) in the Lewis representation of HNO3 molecule respectively are [figure]

  1. 0, 0, -1, +1
  2. 0, -1, 0, +1
  3. 0, +1, 0, -1
  4. +1, 0, 0, -1
JEE Main 2026 (Online) 22nd January Morning Shift

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