A wire of length 'l' and resistance 100 is divided into 10 equal parts. The first 5 parts are connected in series while the next 5 parts are connected in parallel. The two combinations are again connected in series. The resistance of this final combination is:
- 26
- 52
- 55
- 60
Answer
(2) 52
Solution
Resistance of each part = 10010 = 10
5 parts in series: R1 = 5 10 = 50
5 parts in parallel: R2 = 105 = 2
R = R1 + R2 = 50 + 2 = 52
Answer: (2)