From a lot of 10 items, which include 3 defective items, a sample of 5 items is drawn at random. Let the random variable X denote the number of defective items in the sample. If the variance of X is 2, then 96 2 is equal to .
Answer
56
Solution
P(X = r) = 3Cr 7C5-r10C5, 10C5 = 252
X: 0, 1, 2, 3 ⇒ P: 21252, 105252, 105252, 21252 = 112, 512, 512, 112
= xP = 0 + 5 + 10 + 312 = 32, x2P = 0 + 5 + 20 + 912 = 176
2 = x2P - 2 = 176 - 94 = 712
96 2 = 96 712 = 56
Answer: 56