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Coordination Compounds · Question 37

JEE Main 2025 (Online) 7th April Morning ShiftMCQEasy📈 Topic in 10% papers+4−1
1

An octahedral complex having molecular composition Co 5NH3 Cl SO4 has two isomers A and B. The solution of A gives a white precipitate with AgNO3 solution and the solution of B gives white precipitate with BaCl2 solution. The type of isomerism exhibited by the complex is,

  1. Co-ordinate isomerism
  2. Ionisation isomerism
  3. Geometrical isomerism
  4. Linkage isomerism

Answer

(2) Ionisation isomerism

Solution

A gives white AgCl with AgNO3 Cl- is the counter ion:

A = [Co(NH3)5SO4]Cl

B gives white BaSO4 with BaCl2 SO42- is the counter ion:

B = [Co(NH3)5Cl]SO4

Same composition, but different ions in solution because a ligand and the counter ion exchange places ionisation isomerism.

Answer: (2)

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2

The number of paramagnetic complexes among [FeF6]3-, [Fe(CN)6]3-, [Mn(CN)6]3-, [Co(C2O4)3]3-, [MnCl6]3-, and [CoF6]3-, which involve d2sp3 hybridization is .

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3

Match List - I with List - II. Choose the correct answer from the options given below :

  1. A-I, B-III, C-II, D-IV
  2. A-II, B-III, C-IV, D-I
  3. A-I, B-IV, C-IV, D-III
  4. A-III, B-I, C-II, D-IV
JEE Main 2025 (Online) 7th April Evening Shift
4

The number of unpaired electrons responsible for the paramagnetic nature of the following complex species are respectively : [Fe(CN)6]3-, [FeF6]3-, [CoF6]3-, [Mn(CN)6]3-

  1. 1, 5, 4, 2
  2. 1, 4, 4, 2
  3. 1, 5, 5, 2
  4. 1, 1, 4, 2
JEE Main 2025 (Online) 7th April Evening Shift
5

The number of paramagnetic metal complex species among [Co(NH3)6]3+, [Co(C2O4)3]3-, [MnCl6]3-, [Mn(CN)6]3-, [CoF6]3-, [Fe(CN)6]3- and [FeF6]3- with same number of unpaired electrons is .

JEE Main 2025 (Online) 7th April Evening Shift
6

Which one of the following complexes will have o = 0 and = 5.96 B.M.?

  1. [FeF6]4-
  2. [Mn(SCN)6]4-
  3. [Co(NH3)6]3+
  4. [Fe(CN)6]4-
JEE Main 2025 (Online) 4th April Morning Shift
7

Number of stereoisomers possible for the complexes, [CrCl3(py)3] and [CrCl2(ox)2]3- are respectively (py = pyridine, ox = oxalate)

  1. 3 & 3
  2. 2 & 3
  3. 1 & 2
  4. 2 & 2
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8

'X' is the number of electrons in t2g orbitals of the most stable complex ion among [Fe(NH3)6]3+, [FeCl6]3-, [Fe(C2O4)3]3- and [Fe(H2O)6]3+. The nature of oxide of vanadium of the type V2OX is :

  1. Amphoteric
  2. Acidic
  3. Basic
  4. Neutral
JEE Main 2025 (Online) 4th April Evening Shift
9

The correct order of [FeF6]3-, [CoF6]3-, [Ni(CO)4] and [Ni(CN)4]2- complex species based on the number of unpaired electrons present is:

  1. [CoF6]3- > [FeF6]3- > [Ni(CO)4] > [Ni(CN)4]2-
  2. [FeF6]3- > [CoF6]3- > [Ni(CN)4]2- > [Ni(CO)4]
  3. [FeF6]3- > [CoF6]3- > [Ni(CN)4]2- = [Ni(CO)4]
  4. [Ni(CN)4]2- > [FeF6]3- > [CoF6]3- > [Ni(CO)4]
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10

A metal complex with a formula MCl4 3NH3 is involved in sp3d2 hybridisation. It upon reaction with excess of AgNO3 solution gives 'x' moles of AgCl. Consider 'x' is equal to the number of lone pairs of electrons present in the central atom of BrF5. Then the number of geometrical isomers exhibited by the complex is .

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11

The correct order of the complexes [Co(NH3)5(H2O)]3+ (A), [Co(NH3)6]3+ (B), [Co(CN)6]3- (C) and [CoCl(NH3)5]2+ (D) in terms of wavelength of light absorbed is

  1. D > C > B > A
  2. C > B > A > D
  3. D > A > B > C
  4. C > B > D > A
JEE Main 2025 (Online) 3rd April Morning Shift

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