In an experiment it showed that 10 mL of 0.05 M solution of chloride required 10 mL of 0.1 M solution of AgNO3, which of the following will be the formula of the chloride (X stands for the symbol of the element other than chlorine)
- X2Cl2
- XCl2
- XCl4
- X2Cl
Answer
(2) XCl2
Solution
Millimoles of chloride salt = 10 0.05 = 0.5
Millimoles of AgNO3 = 10 0.1 = 1.0
∵ Ag+ + Cl- AgCl, millimoles of Cl- = 1.0
⇒ Cl- per formula unit = 1.00.5 = 2
∴ The formula of the chloride is XCl2.
Answer: (2)