For the redox reaction, MnO4- + C2O42- + H+ Mn2+ + CO2 + H2O The correct coefficients of the reactants for the balanced equation are
- array|c|c|c| MnO4- & C2O42- & H+ \ 16 & 5 & 2 \ array
- array|c|c|c| MnO4- & C2O42- & H+ \ 2 & 5 & 16 \ array
- array|c|c|c| MnO4- & C2O42- & H+ \ 2 & 16 & 5 \ array
- array|c|c|c| MnO4- & C2O42- & H+ \ 5 & 16 & 2 \ array
Answer
(2) array|c|c|c| MnO4- & C2O42- & H+ \ 2 & 5 & 16 \ array
Solution
Reduction half: MnO4- + 8H+ + 5e- Mn2+ + 4H2O … (i)
Oxidation half: C2O42- 2CO2 + 2e- … (ii)
(i) × 2 + (ii) × 5:
2MnO4- + 5C2O42- + 16H+ 2Mn2+ + 10CO2 + 8H2O
∴ Coefficients: MnO4- = 2, C2O42- = 5, H+ = 16
Answer: (2)