Assuming complete ionisation, same moles of which of the following compounds will require the least amount of acidified KMnO4 for complete oxidation?
- FeSO3
- FeC2O4
- Fe(NO2)2
- FeSO4
Answer
(4) FeSO4
Solution
Acidified KMnO4 oxidises every reducing species present; the amount needed is proportional to the total loss of electrons (n-factor) per mole.
FeSO3: Fe2+ Fe3+ (1 e-) and SO32- SO42- (2 e-) ⇒ n = 3
FeC2O4: Fe2+ Fe3+ (1 e-) and C2O42- 2CO2 (2 e-) ⇒ n = 3
Fe(NO2)2: Fe2+ Fe3+ (1 e-) and 2NO2- 2NO3- (2 2 = 4 e-) ⇒ n = 5
FeSO4: only Fe2+ Fe3+ (1 e-); SO42- cannot be oxidised further ⇒ n = 1
∴ FeSO4 has the smallest n-factor and needs the least KMnO4.
Answer: (4)