If a function f satisfies f(m + n) = f(m) + f(n) for all m, n N and f(1) = 1, then the largest natural number such that k = 12022 f( + k) (2022)2 is equal to .
Answer
1010
Solution
f(n) = f(n - 1) + f(1) = = n f(1) = n, so f(x) = x for every natural number x.
k = 12022( + k) = 2022 + 2022 20232 20222
Dividing by 2022: + 20232 2022 20212 = 1010.5
So the largest natural is 1010.
Answer: 1010