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Electrochemistry · Question 43

AIPMT 2011 (Prelims)MCQEasy📈 Topic in 12% papers+4−1
1

Standard electrode potential of three metals X, Y and Z are -1.2 V, +0.5 V and -3.0 V respectively. The reducing power of these metals will be

  1. Y > Z > X
  2. Y > X > Z
  3. Z > X > Y
  4. X > Y > Z

Answer

(3) Z > X > Y

Solution

The lower (more negative) the standard reduction potential, the greater the tendency of the metal to lose electrons stronger reducing agent.

E : Z (-3.0 V) < X (-1.2 V) < Y (+0.5 V)

Reducing power: Z > X > Y

Answer: (3)

AIPMT 2011 (Prelims)

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2

The electrode potentials for Cu2+(aq) + e- Cu+(aq) and Cu+(aq) + e- Cu(s) are +0.15 V and +0.50 V respectively. The value of E Cu2+/Cu will be

  1. 0.500 V
  2. 0.325 V
  3. 0.650 V
  4. 0.150 V
AIPMT 2011 (Prelims)
3

Standard electrode potential for Sn4+/Sn2+ couple is +0.15 V and that for the Cr3+/Cr couple is -0.74 V. These two couples in their standard state are connected to make a cell. The cell potential will be

  1. +1.19 V
  2. +0.89 V
  3. +0.18 V
  4. +1.83 V
AIPMT 2011 (Prelims)
4

Which of the following expressions correctly represents the equivalent conductance at infinite dilution of Al2(SO4)3. Given that Al3+ and SO42- are the equivalent conductances at infinite dilution of the respective ions?

  1. 2 Al3+ + 3 SO42-
  2. Al3+ + SO42-
  3. ( Al3+ + SO42-) 6
  4. 13 Al3+ + 12 SO42-
AIPMT 2010 (Mains)
5

Consider the following relations for emf of an electrochemical cell (i) EMF of cell = (Oxidation potential of anode) − (Reduction potential of cathode) (ii) EMF of cell = (Oxidation potential of anode) + (Reduction potential of cathode) (iii) EMF of cell = (Reduction potential of anode) + (Reduction potential of cathode) (iv) EMF of cell = (Oxidation potential of anode) − (Oxidation potential of cathode) Which of the above relations are correct?

  1. (iii) and (i)
  2. (i) and (ii)
  3. (iii) and (iv)
  4. (ii) and (iv)
AIPMT 2010 (Mains)
6

For the reduction of silver ions with copper metal, the standard cell potential was found to be +0.46 V at 25 C. The value of standard Gibbs energy, G will be (F = 96500 C mol-1)

  1. -89.0 kJ
  2. -89.0 J
  3. -44.5 kJ
  4. -98.0 kJ
AIPMT 2010 (Prelims)
7

An increase in equivalent conductance of a strong electrolyte with dilution is mainly due to

  1. increase in ionic mobility of ions
  2. 100% ionisation of electrolyte at normal dilution
  3. increase in both i.e., number of ions and ionic mobility of ions
  4. increase in number of ions.
AIPMT 2010 (Prelims)
8

Given : (i) Cu2+ + 2e- Cu, E = 0.337 V (ii) Cu2+ + e- Cu+, E = 0.153 V Electrode potential, E for the reaction, Cu+ + e- Cu, will be

  1. 0.90 V
  2. 0.30 V
  3. 0.38 V
  4. 0.52 V
AIPMT 2009
9

Al2O3 is reduced by electrolysis at low potentials and high currents. If 4.0 104 amperes of current is passed through molten Al2O3 for 6 hours, what mass of aluminium is produced? (Assume 100% current efficiency, at. mass of Al = 27 g mol-1).

  1. 8.1 104 g
  2. 2.4 105 g
  3. 1.3 104 g
  4. 9.0 103 g
AIPMT 2009
10

The equivalent conductance of M/32 solution of a weak monobasic acid is 8.0 mho cm2 and at infinite dilution is 400 mho cm2. The dissociation constant of this acid is

  1. 1.25 10-6
  2. 6.25 10-4
  3. 1.25 10-4
  4. 1.25 10-5
AIPMT 2009
11

On the basis of the following E values, the strongest oxidizing agent is [Fe(CN)6]4- [Fe(CN)6]3- + e-; E = -0.35 V Fe2+ Fe3+ + e-; E = -0.77 V

  1. Fe3+
  2. [Fe(CN)6]3-
  3. [Fe(CN)6]4-
  4. Fe2+
AIPMT 2008

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