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Solutions · Question 10

JEE Main 2026 (Online) 2nd April Evening ShiftMCQEasy📈 Topic in 26% papers+4−1
1

Solution A is prepared by dissolving 1 g of a protein (molar mass = 50,000 g mol-1) in 0.5 L of water at 300 K. Its osmotic pressure is x bar. Solution B is made by dissolving 2 g of the same protein in 1 L of water at 300 K. Osmotic pressure of solution B is y bar. Entire solution of A is mixed with entire solution of B at the same temperature. The osmotic pressure of resultant solution is z bar. x, y and z respectively are: (R = 0.083 L bar mol-1 K-1)

  1. 9.96 10-4; 9.96 10-4; 9.96 10-4
  2. 9.96 10-4; 9.96 10-4; 19.92 10-4
  3. 4.98 10-4; 4.98 10-4; 9.96 10-4
  4. 4.98 10-4; 4.98 10-4; 4.98 10-4

Answer

(1) 9.96 10-4; 9.96 10-4; 9.96 10-4

Solution

= CRT, so equal concentrations give equal osmotic pressures.

A: n = 150000 = 2 10-5 mol ⇒ C = 2 10-50.5 = 4 10-5 M

B: n = 250000 = 4 10-5 mol ⇒ C = 4 10-51 = 4 10-5 M

Mixture: n = 6 10-5 mol in 1.5 L ⇒ C = 4 10-5 M

⇒ x = y = z = 4 10-5 0.083 300

= 9.96 10-4 bar

Answer: (1)

JEE Main 2026 (Online) 2nd April Evening Shift

Keep practising — Solutions

2

At T(K), 2 moles of liquid A and 3 moles of liquid B are mixed. The vapour pressure of ideal solution formed is 320 mm Hg. At this stage, one mole of A and one mole of B are added to the solution. The vapour pressure is now measured as 328.6 mm Hg. The vapour pressure (in mm Hg) of A and B are respectively:

  1. 400, 300
  2. 600, 400
  3. 500, 200
  4. 300, 200
JEE Main 2026 (Online) 28th January Morning Shift
3

Consider the following aqueous solutions. I. 2.2 g glucose in 125 mL of solution. II. 1.9 g calcium chloride in 250 mL of solution. III. 9.0 g urea in 500 mL of solution. IV. 20.5 g aluminium sulphate in 750 mL of solution. The correct increasing order of boiling point of these solutions will be : [Given : Molar mass in g mol-1 : H = 1, C = 12, N = 14, O = 16, Cl = 35.5, Ca = 40, Al = 27 and S = 32]

  1. III < I < II < IV
  2. II < III < IV < I
  3. II < III < I < IV
  4. I < II < III < IV
JEE Main 2026 (Online) 28th January Evening Shift
4

A solution is prepared by dissolving 0.3 g of a non-volatile non-electrolyte solute 'A' of molar mass 60 g mol-1 and 0.9 g of a non-volatile non-electrolyte solute 'B' of molar mass 180 g mol-1 in 100 mL H2O at 27 . Osmotic pressure of the solution will be [Given: R = 0.082 L atm K-1 mol-1]

  1. 2.46 atm
  2. 0.82 atm
  3. 1.47 atm
  4. 1.23 atm
JEE Main 2026 (Online) 24th January Morning Shift
5

'W' g of a non-volatile electrolyte solid solute of molar mass 'M' g mol-1 when dissolved in 100 mL water, decreases vapour pressure of water from 640 mm Hg to 600 mm Hg. If aqueous solution of the electrolyte boils at 375 K and Kb for water is 0.52 K kg mol-1, then the mole fraction of the electrolyte solute (x2) in the solution can be expressed as (Given : density of water = 1 g/mL and boiling point of water = 373 K)

  1. 162.6 WM
  2. 1.38 MW
  3. 2.616 MW
  4. 1.38 WM
JEE Main 2026 (Online) 24th January Morning Shift
6

At 298 K, the mole percentage of N2(g) in air is 80\%. Water is in equilibrium with air at a pressure of 10 atm. What is the mole fraction of N2(g) in water at 298 K? (KH for N2 is 6.5 107 mmHg)

  1. 9.35 10-5
  2. 9.35 105
  3. 1.23 10-7
  4. 1.17 10-4
JEE Main 2026 (Online) 24th January Evening Shift
7

Two liquids A and B form an ideal solution at temperature T K. At T K, the vapour pressures of pure A and B are 55 and 15 kN m-2 respectively. What is the mole fraction of A in solution of A and B in equilibrium with a vapour in which the mole fraction of A is 0.8?

  1. 0.5217
  2. 0.480
  3. 0.340
  4. 0.663
JEE Main 2026 (Online) 24th January Evening Shift
8

Which one of the following graphs accurately represents the plot of partial pressure of CS2 vs its mole fraction in a mixture of acetone and CS2 at constant temperature?

  1. [figure]
  2. [figure]
  3. [figure]
  4. [figure]
JEE Main 2026 (Online) 23rd January Morning Shift
9

Two liquids A and B form an ideal solution. At 320 K, the vapour pressure of the solution, containing 3 mol of A and 1 mol of B is 500 mm Hg. At the same temperature, if 1 mol of A is further added to this solution, vapour pressure of the solution increases by 20 mm Hg. Vapour pressure (in mm Hg) of B in pure state is . (Nearest integer)

JEE Main 2026 (Online) 23rd January Evening Shift
10

Consider a solution of CO2(g) dissolved in water in a closed container. Which one of the following plots correctly represents variation of log (partial pressure of CO2 in vapour phase above water) [y-axis] with log (mole fraction of CO2 in water) [x-axis] at 25 ?

  1. [figure]
  2. [figure]
  3. [figure]
  4. [figure]
JEE Main 2026 (Online) 22nd January Morning Shift
11

Given below are two statements : In the light of the above statements, choose the correct answer from the options given below

  1. Both Statement I and Statement II are true
  2. Statement I is true but Statement II is false
  3. Statement I is false but Statement II is true
  4. Both Statement I and Statement II are false
JEE Main 2026 (Online) 22nd January Morning Shift

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