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Amines · Question 23

NEET 2018MCQEasy📈 Topic in 62% papers+4−1
1

Nitration of aniline in strong acidic medium also gives m-nitroaniline because

  1. in spite of substituents nitro group always goes to only m-position
  2. in electrophilic substitution reactions amino group is meta directive
  3. in absence of substituents nitro group always goes to m-position
  4. in acidic (strong) medium aniline is present as anilinium ion

Answer

(4) in acidic (strong) medium aniline is present as anilinium ion

Solution

As per NCERT, in the strongly acidic medium aniline is protonated to form the anilinium ion, C6H5 NH3, which is meta directing.

⇒ That is why, besides the ortho and para derivatives, a significant amount of the meta derivative (m-nitroaniline) is also formed.

Answer: (4)

NEET 2018

Keep practising — Amines

2

The correct increasing order of basic strength for the following compounds is [figure]

  1. III < I < II
  2. III < II < I
  3. II < I < III
  4. II < III < I
NEET 2017
3

Which of the following reactions is appropriate for converting acetamide to methanamine?

  1. Hoffmann hypobromamide reaction
  2. Stephen's reaction
  3. Gabriel phthalimide synthesis
  4. Carbylamine reaction
NEET 2017
4

The correct statement regarding the basicity of arylamines is

  1. arylamines are generally more basic than alkylamines because of aryl group
  2. arylamines are generally more basic than alkylamines, because the nitrogen atom in arylamines is sp-hybridised
  3. arylamines are generally less basic than alkylamines because the nitrogen lone-pair electrons are delocalised by interaction with the aromatic ring -electron system
  4. arylamines are generally more basic than alkylamines because the nitrogen lone-pair electrons are not delocalised by interaction with the aromatic ring -electron system.
NEET 2016 (Phase 1)
5

Which one of the following nitro-compounds does not react with nitrous acid?

  1. [figure]
  2. [figure]
  3. [figure]
  4. [figure]
NEET 2016 (Phase 2)
6

A given nitrogen-containing aromatic compound 'A' reacts with Sn/HCl, followed by HNO2 to give an unstable compound 'B'. 'B', on treatment with phenol, forms a beautiful coloured compound 'C' with the molecular formula C12H10N2O. The structure of compound 'A' is

  1. [figure]
  2. [figure]
  3. [figure]
  4. [figure]
NEET 2016 (Phase 2)
7

The following reaction [figure] is known by the name

  1. Perkin's reaction
  2. Acetylation reaction
  3. Schotten-Baumann reaction
  4. Friedel-Craft's reaction
AIPMT 2015
8

Method by which aniline cannot be prepared is

  1. degradation of benzamide with bromine in alkaline solution
  2. reduction of nitrobenzene with H2/Pd in ethanol
  3. potassium salt of phthalimide treated with chlorobenzene followed by hydrolysis with aqueous NaOH solution
  4. hydrolysis of phenylisocyanide with acidic solution.
AIPMT 2015
9

The electrolytic reduction of nitrobenzene in strongly acidic medium produces

  1. azobenzene
  2. aniline
  3. p-aminophenol
  4. azoxybenzene.
AIPMT 2015 (Cancelled)
10

In the following reaction, the product (A) is [figure]

  1. [figure]
  2. [figure]
  3. [figure]
  4. [figure]
AIPMT 2014
11

Which of the following will be most stable diazonium salt RN2+X-?

  1. CH3N2+X-
  2. C6H5N2+X-
  3. CH3CH2N2+X-
  4. C6H5CH2N2+X-
AIPMT 2014

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