A resistor is connected to a battery of 12 V emf and internal resistance 2 Ω. If the current in the circuit is 0.6 A, the terminal voltage of the battery is :
- 12 V
- 1.2 V
- 10 V
- 10.8 V
Answer
(4) 10.8 V
Solution
When a battery supplies current, the terminal voltage is V = E - Ir
V = 12 - 0.6 2
V = 12 - 1.2
V = 10.8 V
Answer: (4)