Consider two circuits, (A) and (B), each having two resistors. One of them has a positive temperature coefficient of resistance, + , while the other one has a negative temperature of coefficient, - , as shown in the figure. The current through these circuits are denoted by IA and IB. At initial temperature, the resistance of the two resistors is R0. As the temperature is increased, the correct option that describes the variation of current in these circuits is: [figure]
- both IA and IB remain constant
- IA remains constant while IB increases
- IA decreases while IB increases
- IA increases while IB decreases
Answer
(2) IA remains constant while IB increases
Solution
For circuit (A), the two resistors are connected in series:
Req, A = R0(1 - T) + R0(1 + T) = 2R0
Since the equivalent resistance is independent of T, IA = V2R0 remains constant.
For circuit (B), the two resistors are connected in parallel:
1Req, B = 1R0(1 - T) + 1R0(1 + T) = 2R0R02(1 - 2 T2) = 2R0(1 - 2 T2)
IB = VReq, B = 2VR0(1 - 2 T2)
As temperature increases, (1 - 2 T2) decreases, which means IB increases.
Therefore, IA remains constant while IB increases.
Answer: (2)