Coordination Compounds · Question 35

Given below are two statements: In the light of the above statements, choose the correct answer from the options given below:

1. Statement I is true but Statement II is false
2. Both Statement I and Statement II are true
3. Both Statement I and Statement II are false
4. Statement I is false but Statement II is true

An octahedral complex having molecular composition Co 5NH3 Cl SO4 has two isomers A and B. The solution of A gives a white precipitate with AgNO3 solution and the solution of B gives white precipitate with BaCl2 solution. The type of isomerism exhibited by the complex is,

1. Co-ordinate isomerism
2. Ionisation isomerism
3. Geometrical isomerism
4. Linkage isomerism

The number of paramagnetic complexes among [FeF6]3-, [Fe(CN)6]3-, [Mn(CN)6]3-, [Co(C2O4)3]3-, [MnCl6]3-, and [CoF6]3-, which involve d2sp3 hybridization is .

Match List - I with List - II. Choose the correct answer from the options given below :

1. A-I, B-III, C-II, D-IV
2. A-II, B-III, C-IV, D-I
3. A-I, B-IV, C-IV, D-III
4. A-III, B-I, C-II, D-IV

The number of unpaired electrons responsible for the paramagnetic nature of the following complex species are respectively : [Fe(CN)6]3-, [FeF6]3-, [CoF6]3-, [Mn(CN)6]3-

1. 1, 5, 4, 2
2. 1, 4, 4, 2
3. 1, 5, 5, 2
4. 1, 1, 4, 2

The number of paramagnetic metal complex species among [Co(NH3)6]3+, [Co(C2O4)3]3-, [MnCl6]3-, [Mn(CN)6]3-, [CoF6]3-, [Fe(CN)6]3- and [FeF6]3- with same number of unpaired electrons is .

Which one of the following complexes will have o = 0 and = 5.96 B.M.?

1. [FeF6]4-
2. [Mn(SCN)6]4-
3. [Co(NH3)6]3+
4. [Fe(CN)6]4-

Number of stereoisomers possible for the complexes, [CrCl3(py)3] and [CrCl2(ox)2]3- are respectively (py = pyridine, ox = oxalate)

1. 3 & 3
2. 2 & 3
3. 1 & 2
4. 2 & 2

'X' is the number of electrons in t2g orbitals of the most stable complex ion among [Fe(NH3)6]3+, [FeCl6]3-, [Fe(C2O4)3]3- and [Fe(H2O)6]3+. The nature of oxide of vanadium of the type V2OX is :

1. Amphoteric
2. Acidic
3. Basic
4. Neutral

The correct order of [FeF6]3-, [CoF6]3-, [Ni(CO)4] and [Ni(CN)4]2- complex species based on the number of unpaired electrons present is:

1. [CoF6]3- > [FeF6]3- > [Ni(CO)4] > [Ni(CN)4]2-
2. [FeF6]3- > [CoF6]3- > [Ni(CN)4]2- > [Ni(CO)4]
3. [FeF6]3- > [CoF6]3- > [Ni(CN)4]2- = [Ni(CO)4]
4. [Ni(CN)4]2- > [FeF6]3- > [CoF6]3- > [Ni(CO)4]