The number of critical points of the function f(x) = (x - 2)2/3(2x + 1) is
- 2
- 1
- 0
- 3
Answer
(1) 2
Solution
f'(x) = 23(x - 2)-1/3(2x + 1) + 2(x - 2)2/3
= 2(2x + 1) + 6(x - 2)3(x - 2)1/3 = 10(x - 1)3(x - 2)1/3
f'(x) = 0 x = 1
f'(x) is not defined at x = 2, where f is defined, so x = 2 is also a critical point.
Hence there are 2 critical points.
Answer: (1)