Let f(x) = 4 3 x + 3 3 2 x - 10. The number of points of local maxima of f in interval (0, 2 ) is
- 1
- 3
- 4
- 2
Answer
(4) 2
Solution
f'(x) = -12 2 x x - 6 3 x x
= -3 2x (2 x + 3 )
f'(x) = 0 when 2x = 0: x = 2, , 3 2
or when x = - 32: x = 5 6, 7 6
Sign of f'(x) in (0, 2 ):
[figure]
f'(x) changes from + to - only at x = 5 6 and 7 6, so f has 2 points of local maxima.
Answer: (4)