6.02 1020 molecules of urea are present in 100 mL of its solution. The concentration of solution is
- 0.001 M
- 0.1 M
- 0.02 M
- 0.01 M
Answer
(4) 0.01 M
Solution
Moles of urea = 6.02 10206.02 1023 = 10-3 mol
Volume of solution = 100 mL = 0.1 L
⇒ Molarity = 10-3 mol0.1 L
= 0.01 M
Answer: (4)