Atomic number of Cr and Fe are respectively 24 and 26, which of the following is paramagnetic with the spin of electron?
- [Cr(CO)6]
- [Fe(CO)5]
- [Fe(CN)6]4-
- [Cr(NH3)6]3+
Answer
(4) [Cr(NH3)6]3+
Solution
[Cr(CO)6]: Cr(0), 3d6; CO is a strong field ligand t2g6, no unpaired electron (diamagnetic)
[Fe(CO)5]: Fe(0), 3d8; strong field CO pairs all electrons diamagnetic
[Fe(CN)6]4-: Fe2+, 3d6; strong field CN- t2g6, diamagnetic
[Cr(NH3)6]3+: Cr3+, 3d3 t2g3, 3 unpaired electrons whatever the ligand (d²sp³)
Only [Cr(NH3)6]3+ is paramagnetic.
Answer: (4)