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Application of Derivatives

JEE Main 2024 (Online) 9th April Morning ShiftNumericalMedium📈 Topic in 33% papers+4
Ques. 1JEE Main 2024, 9 April (Morning Shift)

Let the set of all positive values of , for which the point of local minimum of the function (1 + x ( 2 - x2 ) ) satisfies x2 + x + 2x2 + 5x + 6 < 0, be ( , ). Then 2 + 2 is equal to .

Answer

39

Solution

f(x) = 1 + 2 x - x3 f'(x) = 2 - 3x2 = 0 x = 3

f''(x) = -6x > 0 at x = - 3, so the local minimum is at x = - 3.

Since x2 + x + 2 > 0 always ( D = 1 - 8 < 0), we need (x + 2)(x + 3) < 0, i.e. -3 < x < -2:

[figure]

-3 < - 3 < -2 2 3 < < 3 3

So = 2 3, = 3 3 and 2 + 2 = 12 + 27 = 39.

Answer: 39

Keep practising — Application of Derivatives

Ques. 2JEE Main 2024, 9 April (Evening Shift)

Let the set of all values of p, for which f(x) = (p2 - 6p + 8 ) ( 2 2x - 2 2x ) + 2(2 - p)x + 7 does not have any critical point, be the interval (a, b). Then 16ab is equal to .

Ques. 3JEE Main 2024, 8 April (Morning Shift)

Let f(x) = 4 3 x + 3 3 2 x - 10. The number of points of local maxima of f in interval (0, 2 ) is

  1. 1
  2. 3
  3. 4
  4. 2
Ques. 4JEE Main 2024, 8 April (Morning Shift)

The number of critical points of the function f(x) = (x - 2)2/3(2x + 1) is

  1. 2
  2. 1
  3. 0
  4. 3
Ques. 5JEE Main 2024, 8 April (Morning Shift)

For the function f(x) = ( x) - x + 1, x R, between the following two statements (S1) f(x) = 0 for only one value of x in [0, ]. (S2) f(x) is decreasing in [0, 2 ] and increasing in [ 2, ].

  1. Both (S1) and (S2) are incorrect.
  2. Only (S1) is correct.
  3. Only (S2) is correct.
  4. Both (S1) and (S2) are correct.
Ques. 6JEE Main 2024, 8 April (Evening Shift)

If the function f(x) = 2x3 - 9ax2 + 12a2x + 1, a > 0 has a local maximum at x = and a local minimum at x = 2, then and 2 are the roots of the equation :

  1. x2 - 6x + 8 = 0
  2. 8x2 - 6x + 1 = 0
  3. 8x2 + 6x - 1 = 0
  4. x2 + 6x + 8 = 0
Ques. 7JEE Main 2024, 8 April (Evening Shift)

Let A be the region enclosed by the parabola y2 = 2x and the line x = 24. Then the maximum area of the rectangle inscribed in the region A is .

Ques. 8JEE Main 2024, 6 April (Morning Shift)

The interval in which the function f(x) = xx, x > 0, is strictly increasing is

  1. (0, )
  2. (0, 1e ]
  3. [ 1e2, 1 )
  4. [ 1e, )
Ques. 9JEE Main 2024, 6 April (Evening Shift)

If the function f(x) = ( 1x )2x; x > 0 attains the maximum value at x = 1e then :

  1. e < e
  2. e2 < (2 )e
  3. (2e) > (2e)
  4. e > e
Ques. 10JEE Main 2024, 5 April (Morning Shift)

Let a rectangle ABCD of sides 2 and 4 be inscribed in another rectangle PQRS such that the vertices of the rectangle ABCD lie on the sides of the rectangle PQRS. Let a and b be the sides of the rectangle PQRS when its area is maximum. Then (a + b)2 is equal to :

  1. 64
  2. 80
  3. 60
  4. 72
Ques. 11JEE Main 2024, 5 April (Morning Shift)

For the function f(x) = x + 3x - 2 (x2 + x ), where x [0, 2 ], consider the following two statements : (I) f is increasing in (0, 2 ). (II) f' is decreasing in (0, 2 ). Between the above two statements,

  1. only (I) is true.
  2. both (I) and (II) are true.
  3. only (II) is true.
  4. neither (I) nor (II) is true.

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