Three balls are drawn at random from a bag containing 5 blue and 4 yellow balls. Let the random variables X and Y respectively denote the number of blue and yellow balls. If X and Y are the means of X and Y respectively, then 7 X + 4 Y is equal to .
Answer
17
Solution
Total ways = 9C3 = 84
P(X = 0) = 4C384 = 484, P(X = 1) = 5C1 4C284 = 3084
P(X = 2) = 5C2 4C184 = 4084, P(X = 3) = 5C384 = 1084
X = x P(x) = 0 + 30 + 80 + 3084 = 14084 = 53
X + Y = 3 Y = 3 - 53 = 43
7 X + 4 Y = 353 + 163 = 17
Answer: 17